Derivative of y=x/sqrt(2x-1)

1. Apply the quotient rule, which is:

   $$\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}$$

   $f{\left(x \right)} = x$ and $g{\left(x \right)} = \sqrt{2 x - 1}$.

   To find $\frac{d}{d x} f{\left(x \right)}$:

   1. Apply the power rule: $x$ goes to $1$

   To find $\frac{d}{d x} g{\left(x \right)}$:

   1. Let $u = 2 x - 1$.

   2. Apply the power rule: $\sqrt{u}$ goes to $\frac{1}{2 \sqrt{u}}$

   3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \left(2 x - 1\right)$:

      1. Differentiate $2 x - 1$ term by term:

         1. The derivative of the constant $-1$ is zero.

         2. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: $x$ goes to $1$

            So, the result is: $2$

         The result is: $2$

      The result of the chain rule is:

      $$\frac{1}{\sqrt{2 x - 1}}$$

   Now plug in to the quotient rule:

   $\frac{- \frac{x}{\sqrt{2 x - 1}} + \sqrt{2 x - 1}}{2 x - 1}$

2. Now simplify:

   $$\frac{x - 1}{\left(2 x - 1\right)^{\frac{3}{2}}}$$

The answer is:

$$\frac{x - 1}{\left(2 x - 1\right)^{\frac{3}{2}}}$$