Derivative of y=sqrt(3x+1)

1. Let $u = 3 x + 1$.

2. Apply the power rule: $\sqrt{u}$ goes to $\frac{1}{2 \sqrt{u}}$

3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \left(3 x + 1\right)$:

   1. Differentiate $3 x + 1$ term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

         1. Apply the power rule: $x$ goes to $1$

         So, the result is: $3$

      2. The derivative of the constant $1$ is zero.

      The result is: $3$

   The result of the chain rule is:

   $$\frac{3}{2 \sqrt{3 x + 1}}$$

4. Now simplify:

   $$\frac{3}{2 \sqrt{3 x + 1}}$$

The answer is:

$$\frac{3}{2 \sqrt{3 x + 1}}$$