Derivative of y=e^(5x)⋅(3x+4).

1. Apply the product rule:

   $$\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}$$

   $f{\left(x \right)} = e^{5 x}$; to find $\frac{d}{d x} f{\left(x \right)}$:

   1. Let $u = 5 x$.

   2. The derivative of $e^{u}$ is itself.

   3. Then, apply the chain rule. Multiply by $\frac{d}{d x} 5 x$:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

         1. Apply the power rule: $x$ goes to $1$

         So, the result is: $5$

      The result of the chain rule is:

      $$5 e^{5 x}$$

   $g{\left(x \right)} = 3 x + 4$; to find $\frac{d}{d x} g{\left(x \right)}$:

   1. Differentiate $3 x + 4$ term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

         1. Apply the power rule: $x$ goes to $1$

         So, the result is: $3$

      2. The derivative of the constant $4$ is zero.

      The result is: $3$

   The result is: $5 \cdot \left(3 x + 4\right) e^{5 x} + 3 e^{5 x}$

2. Now simplify:

   $$\left(15 x + 23\right) e^{5 x}$$

The answer is:

$$\left(15 x + 23\right) e^{5 x}$$