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(x^2+x+2)/(x-1)

Derivative of (x^2+x+2)/(x-1)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 2        
x  + x + 2
----------
  x - 1   
$$\frac{\left(x^{2} + x\right) + 2}{x - 1}$$
(x^2 + x + 2)/(x - 1)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      3. Apply the power rule: goes to

      The result is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
           2        
1 + 2*x   x  + x + 2
------- - ----------
 x - 1            2 
           (x - 1)  
$$\frac{2 x + 1}{x - 1} - \frac{\left(x^{2} + x\right) + 2}{\left(x - 1\right)^{2}}$$
The second derivative [src]
  /             2          \
  |    2 + x + x    1 + 2*x|
2*|1 + ---------- - -------|
  |            2     -1 + x|
  \    (-1 + x)            /
----------------------------
           -1 + x           
$$\frac{2 \left(1 - \frac{2 x + 1}{x - 1} + \frac{x^{2} + x + 2}{\left(x - 1\right)^{2}}\right)}{x - 1}$$
The third derivative [src]
  /                        2\
  |     1 + 2*x   2 + x + x |
6*|-1 + ------- - ----------|
  |      -1 + x           2 |
  \               (-1 + x)  /
-----------------------------
                  2          
          (-1 + x)           
$$\frac{6 \left(-1 + \frac{2 x + 1}{x - 1} - \frac{x^{2} + x + 2}{\left(x - 1\right)^{2}}\right)}{\left(x - 1\right)^{2}}$$
The graph
Derivative of (x^2+x+2)/(x-1)