2 x + 1 ------ x - 1
/ 2 \ d |x + 1| --|------| dx\x - 1 /
Apply the quotient rule, which is:
and .
To find :
Differentiate term by term:
The derivative of the constant is zero.
Apply the power rule: goes to
The result is:
To find :
Differentiate term by term:
The derivative of the constant is zero.
Apply the power rule: goes to
The result is:
Now plug in to the quotient rule:
The answer is:
2
x + 1 2*x
- -------- + -----
2 x - 1
(x - 1)
/ 2 \
| 1 + x 2*x |
2*|1 + --------- - ------|
| 2 -1 + x|
\ (-1 + x) /
--------------------------
-1 + x
/ 2 \
| 1 + x 2*x |
6*|-1 - --------- + ------|
| 2 -1 + x|
\ (-1 + x) /
---------------------------
2
(-1 + x)