x 2 + 1
2^x + 1
Differentiate 2x+12^{x} + 12x+1 term by term:
ddx2x=2xlog(2)\frac{d}{d x} 2^{x} = 2^{x} \log{\left(2 \right)}dxd2x=2xlog(2)
The derivative of the constant 111 is zero.
The result is: 2xlog(2)2^{x} \log{\left(2 \right)}2xlog(2)
The answer is:
x 2 *log(2)
x 2 2 *log (2)
x 3 2 *log (2)