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Derivative of (x^2-2x+4)^4

Function f() - derivative -N order at the point
v

The graph:

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The solution

You have entered [src]
              4
/ 2          \ 
\x  - 2*x + 4/ 
$$\left(\left(x^{2} - 2 x\right) + 4\right)^{4}$$
(x^2 - 2*x + 4)^4
Detail solution
  1. Let .

  2. Apply the power rule: goes to

  3. Then, apply the chain rule. Multiply by :

    1. Differentiate term by term:

      1. Differentiate term by term:

        1. Apply the power rule: goes to

        2. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result is:

      2. The derivative of the constant is zero.

      The result is:

    The result of the chain rule is:

  4. Now simplify:


The answer is:

The graph
The first derivative [src]
              3           
/ 2          \            
\x  - 2*x + 4/ *(-8 + 8*x)
$$\left(8 x - 8\right) \left(\left(x^{2} - 2 x\right) + 4\right)^{3}$$
The second derivative [src]
                2                             
  /     2      \  /     2                   2\
8*\4 + x  - 2*x/ *\4 + x  - 2*x + 6*(-1 + x) /
$$8 \left(x^{2} - 2 x + 4\right)^{2} \left(x^{2} - 2 x + 6 \left(x - 1\right)^{2} + 4\right)$$
The third derivative [src]
            /     2      \ /              2             2\
48*(-1 + x)*\4 + x  - 2*x/*\12 - 6*x + 3*x  + 4*(-1 + x) /
$$48 \left(x - 1\right) \left(x^{2} - 2 x + 4\right) \left(3 x^{2} - 6 x + 4 \left(x - 1\right)^{2} + 12\right)$$