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Derivative of x^2/3-sin(2*x)

Function f() - derivative -N order at the point
v

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The solution

You have entered [src]
 2           
x            
-- - sin(2*x)
3            
x23sin(2x)\frac{x^{2}}{3} - \sin{\left(2 x \right)}
x^2/3 - sin(2*x)
Detail solution
  1. Differentiate x23sin(2x)\frac{x^{2}}{3} - \sin{\left(2 x \right)} term by term:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: x2x^{2} goes to 2x2 x

      So, the result is: 2x3\frac{2 x}{3}

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let u=2xu = 2 x.

      2. The derivative of sine is cosine:

        ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

      3. Then, apply the chain rule. Multiply by ddx2x\frac{d}{d x} 2 x:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: xx goes to 11

          So, the result is: 22

        The result of the chain rule is:

        2cos(2x)2 \cos{\left(2 x \right)}

      So, the result is: 2cos(2x)- 2 \cos{\left(2 x \right)}

    The result is: 2x32cos(2x)\frac{2 x}{3} - 2 \cos{\left(2 x \right)}


The answer is:

2x32cos(2x)\frac{2 x}{3} - 2 \cos{\left(2 x \right)}

The graph
02468-8-6-4-2-1010-5050
The first derivative [src]
              2*x
-2*cos(2*x) + ---
               3 
2x32cos(2x)\frac{2 x}{3} - 2 \cos{\left(2 x \right)}
The second derivative [src]
2*(1/3 + 2*sin(2*x))
2(2sin(2x)+13)2 \left(2 \sin{\left(2 x \right)} + \frac{1}{3}\right)
The third derivative [src]
8*cos(2*x)
8cos(2x)8 \cos{\left(2 x \right)}