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Derivative of x^3-2cos2x

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 3             
x  - 2*cos(2*x)
$$x^{3} - 2 \cos{\left(2 x \right)}$$
x^3 - 2*cos(2*x)
Detail solution
  1. Differentiate term by term:

    1. Apply the power rule: goes to

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. The derivative of cosine is negative sine:

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result of the chain rule is:

      So, the result is:

    The result is:


The answer is:

The graph
The first derivative [src]
   2             
3*x  + 4*sin(2*x)
$$3 x^{2} + 4 \sin{\left(2 x \right)}$$
The second derivative [src]
2*(3*x + 4*cos(2*x))
$$2 \left(3 x + 4 \cos{\left(2 x \right)}\right)$$
The third derivative [src]
2*(3 - 8*sin(2*x))
$$2 \left(3 - 8 \sin{\left(2 x \right)}\right)$$