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x^3/(x+1)^2

Derivative of x^3/(x+1)^2

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
    3   
   x    
--------
       2
(x + 1) 
$$\frac{x^{3}}{\left(x + 1\right)^{2}}$$
x^3/(x + 1)^2
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Apply the power rule: goes to

    To find :

    1. Let .

    2. Apply the power rule: goes to

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of the constant is zero.

        2. Apply the power rule: goes to

        The result is:

      The result of the chain rule is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
     2      3           
  3*x      x *(-2 - 2*x)
-------- + -------------
       2             4  
(x + 1)       (x + 1)   
$$\frac{x^{3} \left(- 2 x - 2\right)}{\left(x + 1\right)^{4}} + \frac{3 x^{2}}{\left(x + 1\right)^{2}}$$
The second derivative [src]
    /        2           \
    |       x        2*x |
6*x*|1 + -------- - -----|
    |           2   1 + x|
    \    (1 + x)         /
--------------------------
                2         
         (1 + x)          
$$\frac{6 x \left(\frac{x^{2}}{\left(x + 1\right)^{2}} - \frac{2 x}{x + 1} + 1\right)}{\left(x + 1\right)^{2}}$$
The third derivative [src]
  /                 3          2  \
  |     6*x      4*x        9*x   |
6*|1 - ----- - -------- + --------|
  |    1 + x          3          2|
  \            (1 + x)    (1 + x) /
-----------------------------------
                     2             
              (1 + x)              
$$\frac{6 \left(- \frac{4 x^{3}}{\left(x + 1\right)^{3}} + \frac{9 x^{2}}{\left(x + 1\right)^{2}} - \frac{6 x}{x + 1} + 1\right)}{\left(x + 1\right)^{2}}$$
The graph
Derivative of x^3/(x+1)^2