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(x+1)^2/(x-1)

Derivative of (x+1)^2/(x-1)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
       2
(x + 1) 
--------
 x - 1  
$$\frac{\left(x + 1\right)^{2}}{x - 1}$$
(x + 1)^2/(x - 1)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Let .

    2. Apply the power rule: goes to

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of the constant is zero.

        2. Apply the power rule: goes to

        The result is:

      The result of the chain rule is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
                 2
2 + 2*x   (x + 1) 
------- - --------
 x - 1           2
          (x - 1) 
$$\frac{2 x + 2}{x - 1} - \frac{\left(x + 1\right)^{2}}{\left(x - 1\right)^{2}}$$
The second derivative [src]
  /            2            \
  |     (1 + x)    2*(1 + x)|
2*|1 + --------- - ---------|
  |            2     -1 + x |
  \    (-1 + x)             /
-----------------------------
            -1 + x           
$$\frac{2 \left(1 - \frac{2 \left(x + 1\right)}{x - 1} + \frac{\left(x + 1\right)^{2}}{\left(x - 1\right)^{2}}\right)}{x - 1}$$
The third derivative [src]
  /             2            \
  |      (1 + x)    2*(1 + x)|
6*|-1 - --------- + ---------|
  |             2     -1 + x |
  \     (-1 + x)             /
------------------------------
                  2           
          (-1 + x)            
$$\frac{6 \left(-1 + \frac{2 \left(x + 1\right)}{x - 1} - \frac{\left(x + 1\right)^{2}}{\left(x - 1\right)^{2}}\right)}{\left(x - 1\right)^{2}}$$
The graph
Derivative of (x+1)^2/(x-1)