Mister Exam

Derivative of (x-3)/(x+4)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
x - 3
-----
x + 4
x3x+4\frac{x - 3}{x + 4}
(x - 3)/(x + 4)
Detail solution
  1. Apply the quotient rule, which is:

    ddxf(x)g(x)=f(x)ddxg(x)+g(x)ddxf(x)g2(x)\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}

    f(x)=x3f{\left(x \right)} = x - 3 and g(x)=x+4g{\left(x \right)} = x + 4.

    To find ddxf(x)\frac{d}{d x} f{\left(x \right)}:

    1. Differentiate x3x - 3 term by term:

      1. The derivative of the constant 3-3 is zero.

      2. Apply the power rule: xx goes to 11

      The result is: 11

    To find ddxg(x)\frac{d}{d x} g{\left(x \right)}:

    1. Differentiate x+4x + 4 term by term:

      1. The derivative of the constant 44 is zero.

      2. Apply the power rule: xx goes to 11

      The result is: 11

    Now plug in to the quotient rule:

    7(x+4)2\frac{7}{\left(x + 4\right)^{2}}


The answer is:

7(x+4)2\frac{7}{\left(x + 4\right)^{2}}

The graph
02468-8-6-4-2-1010-20002000
The first derivative [src]
  1      x - 3  
----- - --------
x + 4          2
        (x + 4) 
x3(x+4)2+1x+4- \frac{x - 3}{\left(x + 4\right)^{2}} + \frac{1}{x + 4}
The second derivative [src]
  /     -3 + x\
2*|-1 + ------|
  \     4 + x /
---------------
           2   
    (4 + x)    
2(x3x+41)(x+4)2\frac{2 \left(\frac{x - 3}{x + 4} - 1\right)}{\left(x + 4\right)^{2}}
The third derivative [src]
  /    -3 + x\
6*|1 - ------|
  \    4 + x /
--------------
          3   
   (4 + x)    
6(x3x+4+1)(x+4)3\frac{6 \left(- \frac{x - 3}{x + 4} + 1\right)}{\left(x + 4\right)^{3}}
The graph
Derivative of (x-3)/(x+4)