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Derivative of:
Derivative of e^(-x)
Derivative of e^x^2
Derivative of sin(x)/cos(x)
Derivative of cos(x)^(3)
Identical expressions
(two *x+ two)/(x- three)
(2 multiply by x plus 2) divide by (x minus 3)
(two multiply by x plus two) divide by (x minus three)
(2x+2)/(x-3)
2x+2/x-3
(2*x+2) divide by (x-3)
Similar expressions
(2*x+2)/(x+3)
(2*x-2)/(x-3)

The derivative of the function/ (2*x+2)/(x-3)

Derivative of (2*x+2)/(x-3)

The solution

You have entered [src]

2*x + 2
-------
 x - 3

$$\frac{2 x + 2}{x - 3}$$

(2*x + 2)/(x - 3)

Detail solution

Apply the quotient rule, which is:

$\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}$

$f{\left(x \right)} = 2 x + 2$ and $g{\left(x \right)} = x - 3$ .

To find $\frac{d}{d x} f{\left(x \right)}$ :
1. Differentiate $2 x + 2$ term by term:
  1. The derivative of the constant $2$ is zero.
  2. The derivative of a constant times a function is the constant times the derivative of the function.
    1. Apply the power rule: $x$ goes to $1$
    So, the result is: $2$
  The result is: $2$
To find $\frac{d}{d x} g{\left(x \right)}$ :
1. Differentiate $x - 3$ term by term:
  1. The derivative of the constant $-3$ is zero.
  2. Apply the power rule: $x$ goes to $1$
  The result is: $1$
Now plug in to the quotient rule:

$- \frac{8}{\left(x - 3\right)^{2}}$

The answer is:

$- \frac{8}{\left(x - 3\right)^{2}}$

The graph

Plot the graph f(x)

Plot the graph f'(x)

The first derivative [src]

  2     2*x + 2 
----- - --------
x - 3          2
        (x - 3)

$$\frac{2}{x - 3} - \frac{2 x + 2}{\left(x - 3\right)^{2}}$$

Simplify

The second derivative [src]

  /     1 + x \
4*|-1 + ------|
  \     -3 + x/
---------------
           2   
   (-3 + x)

$$\frac{4 \left(-1 + \frac{x + 1}{x - 3}\right)}{\left(x - 3\right)^{2}}$$

Simplify

3-я производная [src]

   /    1 + x \
12*|1 - ------|
   \    -3 + x/
---------------
           3   
   (-3 + x)

$$\frac{12 \left(1 - \frac{x + 1}{x - 3}\right)}{\left(x - 3\right)^{3}}$$

Simplify

The third derivative [src]

   /    1 + x \
12*|1 - ------|
   \    -3 + x/
---------------
           3   
   (-3 + x)

$$\frac{12 \left(1 - \frac{x + 1}{x - 3}\right)}{\left(x - 3\right)^{3}}$$

Simplify