Mister Exam

Derivative of tan(2*x+4)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
tan(2*x + 4)
$$\tan{\left(2 x + 4 \right)}$$
tan(2*x + 4)
Detail solution
  1. Rewrite the function to be differentiated:

  2. Apply the quotient rule, which is:

    and .

    To find :

    1. Let .

    2. The derivative of sine is cosine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    To find :

    1. Let .

    2. The derivative of cosine is negative sine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    Now plug in to the quotient rule:

  3. Now simplify:


The answer is:

The graph
The first derivative [src]
         2         
2 + 2*tan (2*x + 4)
$$2 \tan^{2}{\left(2 x + 4 \right)} + 2$$
The second derivative [src]
  /       2           \               
8*\1 + tan (2*(2 + x))/*tan(2*(2 + x))
$$8 \left(\tan^{2}{\left(2 \left(x + 2\right) \right)} + 1\right) \tan{\left(2 \left(x + 2\right) \right)}$$
The third derivative [src]
   /       2           \ /         2           \
16*\1 + tan (2*(2 + x))/*\1 + 3*tan (2*(2 + x))/
$$16 \left(\tan^{2}{\left(2 \left(x + 2\right) \right)} + 1\right) \left(3 \tan^{2}{\left(2 \left(x + 2\right) \right)} + 1\right)$$
The graph
Derivative of tan(2*x+4)