Derivative of (x+3)^2*(x+5)-1

1. Differentiate $\left(x + 3\right)^{2} \left(x + 5\right) - 1$ term by term:

   1. Apply the product rule:

      $$\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}$$

      $f{\left(x \right)} = \left(x + 3\right)^{2}$; to find $\frac{d}{d x} f{\left(x \right)}$:

      1. Let $u = x + 3$.

      2. Apply the power rule: $u^{2}$ goes to $2 u$

      3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \left(x + 3\right)$:

         1. Differentiate $x + 3$ term by term:

            1. Apply the power rule: $x$ goes to $1$

            2. The derivative of the constant $3$ is zero.

            The result is: $1$

         The result of the chain rule is:

         $$2 x + 6$$

      $g{\left(x \right)} = x + 5$; to find $\frac{d}{d x} g{\left(x \right)}$:

      1. Differentiate $x + 5$ term by term:

         1. Apply the power rule: $x$ goes to $1$

         2. The derivative of the constant $5$ is zero.

         The result is: $1$

      The result is: $\left(x + 3\right)^{2} + \left(x + 5\right) \left(2 x + 6\right)$

   2. The derivative of the constant $-1$ is zero.

   The result is: $\left(x + 3\right)^{2} + \left(x + 5\right) \left(2 x + 6\right)$

2. Now simplify:

   $$\left(x + 3\right) \left(3 x + 13\right)$$

The answer is:

$$\left(x + 3\right) \left(3 x + 13\right)$$