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Derivative of sinx+1/2*sin2x

Function f() - derivative -N order at the point
v

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The solution

You have entered [src]
         sin(2*x)
sin(x) + --------
            2    
sin(x)+sin(2x)2\sin{\left(x \right)} + \frac{\sin{\left(2 x \right)}}{2}
sin(x) + sin(2*x)/2
Detail solution
  1. Differentiate sin(x)+sin(2x)2\sin{\left(x \right)} + \frac{\sin{\left(2 x \right)}}{2} term by term:

    1. The derivative of sine is cosine:

      ddxsin(x)=cos(x)\frac{d}{d x} \sin{\left(x \right)} = \cos{\left(x \right)}

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let u=2xu = 2 x.

      2. The derivative of sine is cosine:

        ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

      3. Then, apply the chain rule. Multiply by ddx2x\frac{d}{d x} 2 x:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: xx goes to 11

          So, the result is: 22

        The result of the chain rule is:

        2cos(2x)2 \cos{\left(2 x \right)}

      So, the result is: cos(2x)\cos{\left(2 x \right)}

    The result is: cos(x)+cos(2x)\cos{\left(x \right)} + \cos{\left(2 x \right)}


The answer is:

cos(x)+cos(2x)\cos{\left(x \right)} + \cos{\left(2 x \right)}

The graph
02468-8-6-4-2-10105-5
The first derivative [src]
cos(x) + cos(2*x)
cos(x)+cos(2x)\cos{\left(x \right)} + \cos{\left(2 x \right)}
The second derivative [src]
-(2*sin(2*x) + sin(x))
(sin(x)+2sin(2x))- (\sin{\left(x \right)} + 2 \sin{\left(2 x \right)})
The third derivative [src]
-(4*cos(2*x) + cos(x))
(cos(x)+4cos(2x))- (\cos{\left(x \right)} + 4 \cos{\left(2 x \right)})