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Derivative of sin^1(2x+3)^3

Function f() - derivative -N order at the point
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The solution

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   1         
sin (2*x + 3)
sin1(2x+3)\sin^{1}{\left(2 x + 3 \right)}
sin(2*x + 3)^1
Detail solution
  1. Let u=sin(2x+3)u = \sin{\left(2 x + 3 \right)}.

  2. Apply the power rule: uu goes to 11

  3. Then, apply the chain rule. Multiply by ddxsin(2x+3)\frac{d}{d x} \sin{\left(2 x + 3 \right)}:

    1. Let u=2x+3u = 2 x + 3.

    2. The derivative of sine is cosine:

      ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

    3. Then, apply the chain rule. Multiply by ddx(2x+3)\frac{d}{d x} \left(2 x + 3\right):

      1. Differentiate 2x+32 x + 3 term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: xx goes to 11

          So, the result is: 22

        2. The derivative of the constant 33 is zero.

        The result is: 22

      The result of the chain rule is:

      2cos(2x+3)2 \cos{\left(2 x + 3 \right)}

    The result of the chain rule is:

    2cos(2x+3)2 \cos{\left(2 x + 3 \right)}

  4. Now simplify:

    2cos(2x+3)2 \cos{\left(2 x + 3 \right)}


The answer is:

2cos(2x+3)2 \cos{\left(2 x + 3 \right)}

The graph
02468-8-6-4-2-10105-5
The first derivative [src]
2*cos(2*x + 3)
2cos(2x+3)2 \cos{\left(2 x + 3 \right)}
The second derivative [src]
-4*sin(3 + 2*x)
4sin(2x+3)- 4 \sin{\left(2 x + 3 \right)}
The third derivative [src]
-8*cos(3 + 2*x)
8cos(2x+3)- 8 \cos{\left(2 x + 3 \right)}