Derivative of sin(3*x-2pi)+pi

1. Differentiate $\sin{\left(3 x - 2 \pi \right)} + \pi$ term by term:

   1. Let $u = 3 x - 2 \pi$.

   2. The derivative of sine is cosine:

      $$\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}$$

   3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \left(3 x - 2 \pi\right)$:

      1. Differentiate $3 x - 2 \pi$ term by term:

         1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: $x$ goes to $1$

            So, the result is: $3$

         2. The derivative of the constant $- 2 \pi$ is zero.

         The result is: $3$

      The result of the chain rule is:

      $$3 \cos{\left(3 x \right)}$$

   4. The derivative of the constant $\pi$ is zero.

   The result is: $3 \cos{\left(3 x \right)}$

The answer is:

$$3 \cos{\left(3 x \right)}$$