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Derivative of sin(3*x-2*pi)+pi

Function f() - derivative -N order at the point
v

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The solution

You have entered [src]
sin(3*x - 2*pi) + pi
$$\sin{\left(3 x - 2 \pi \right)} + \pi$$
sin(3*x - 2*pi) + pi
Detail solution
  1. Differentiate term by term:

    1. Let .

    2. The derivative of sine is cosine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    4. The derivative of the constant is zero.

    The result is:


The answer is:

The graph
The first derivative [src]
3*cos(3*x)
$$3 \cos{\left(3 x \right)}$$
The second derivative [src]
-9*sin(3*x)
$$- 9 \sin{\left(3 x \right)}$$
The third derivative [src]
-27*cos(3*x)
$$- 27 \cos{\left(3 x \right)}$$