Derivative of sin(4*x-1)^(3)

1. Let $u = \sin{\left(4 x - 1 \right)}$.

2. Apply the power rule: $u^{3}$ goes to $3 u^{2}$

3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \sin{\left(4 x - 1 \right)}$:

   1. Let $u = 4 x - 1$.

   2. The derivative of sine is cosine:

      $$\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}$$

   3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \left(4 x - 1\right)$:

      1. Differentiate $4 x - 1$ term by term:

         1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: $x$ goes to $1$

            So, the result is: $4$

         2. The derivative of the constant $-1$ is zero.

         The result is: $4$

      The result of the chain rule is:

      $$4 \cos{\left(4 x - 1 \right)}$$

   The result of the chain rule is:

   $$12 \sin^{2}{\left(4 x - 1 \right)} \cos{\left(4 x - 1 \right)}$$

4. Now simplify:

   $$12 \sin^{2}{\left(4 x - 1 \right)} \cos{\left(4 x - 1 \right)}$$

The answer is: