Mister Exam

Derivative of sin(a*x+b)/a

Function f() - derivative -N order at the point
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Piecewise:

The solution

You have entered [src]
sin(a*x + b)
------------
     a      
sin(ax+b)a\frac{\sin{\left(a x + b \right)}}{a}
sin(a*x + b)/a
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Let u=ax+bu = a x + b.

    2. The derivative of sine is cosine:

      ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

    3. Then, apply the chain rule. Multiply by x(ax+b)\frac{\partial}{\partial x} \left(a x + b\right):

      1. Differentiate ax+ba x + b term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: xx goes to 11

          So, the result is: aa

        2. The derivative of the constant bb is zero.

        The result is: aa

      The result of the chain rule is:

      acos(ax+b)a \cos{\left(a x + b \right)}

    So, the result is: cos(ax+b)\cos{\left(a x + b \right)}

  2. Now simplify:

    cos(ax+b)\cos{\left(a x + b \right)}


The answer is:

cos(ax+b)\cos{\left(a x + b \right)}

The first derivative [src]
cos(a*x + b)
cos(ax+b)\cos{\left(a x + b \right)}
The second derivative [src]
-a*sin(b + a*x)
asin(ax+b)- a \sin{\left(a x + b \right)}
The third derivative [src]
  2             
-a *cos(b + a*x)
a2cos(ax+b)- a^{2} \cos{\left(a x + b \right)}