Mister Exam

Derivative of sin(2pi*z)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
sin(2*pi*z)
sin(2πz)\sin{\left(2 \pi z \right)}
sin((2*pi)*z)
Detail solution
  1. Let u=2πzu = 2 \pi z.

  2. The derivative of sine is cosine:

    ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

  3. Then, apply the chain rule. Multiply by ddz2πz\frac{d}{d z} 2 \pi z:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: zz goes to 11

      So, the result is: 2π2 \pi

    The result of the chain rule is:

    2πcos(2πz)2 \pi \cos{\left(2 \pi z \right)}

  4. Now simplify:

    2πcos(2πz)2 \pi \cos{\left(2 \pi z \right)}


The answer is:

2πcos(2πz)2 \pi \cos{\left(2 \pi z \right)}

The graph
02468-8-6-4-2-1010-1010
The first derivative [src]
2*pi*cos(2*pi*z)
2πcos(2πz)2 \pi \cos{\left(2 \pi z \right)}
The second derivative [src]
     2            
-4*pi *sin(2*pi*z)
4π2sin(2πz)- 4 \pi^{2} \sin{\left(2 \pi z \right)}
The third derivative [src]
     3            
-8*pi *cos(2*pi*z)
8π3cos(2πz)- 8 \pi^{3} \cos{\left(2 \pi z \right)}