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Derivative of 1/(2+x^2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
  1   
------
     2
2 + x 
$$\frac{1}{x^{2} + 2}$$
1/(2 + x^2)
Detail solution
  1. Let .

  2. Apply the power rule: goes to

  3. Then, apply the chain rule. Multiply by :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    The result of the chain rule is:


The answer is:

The graph
The first derivative [src]
   -2*x  
---------
        2
/     2\ 
\2 + x / 
$$- \frac{2 x}{\left(x^{2} + 2\right)^{2}}$$
The second derivative [src]
  /         2 \
  |      4*x  |
2*|-1 + ------|
  |          2|
  \     2 + x /
---------------
           2   
   /     2\    
   \2 + x /    
$$\frac{2 \left(\frac{4 x^{2}}{x^{2} + 2} - 1\right)}{\left(x^{2} + 2\right)^{2}}$$
The third derivative [src]
     /        2 \
     |     2*x  |
24*x*|1 - ------|
     |         2|
     \    2 + x /
-----------------
            3    
    /     2\     
    \2 + x /     
$$\frac{24 x \left(- \frac{2 x^{2}}{x^{2} + 2} + 1\right)}{\left(x^{2} + 2\right)^{3}}$$
4-я производная [src]
   /        2          4  \
   |    12*x       16*x   |
24*|1 - ------ + ---------|
   |         2           2|
   |    2 + x    /     2\ |
   \             \2 + x / /
---------------------------
                 3         
         /     2\          
         \2 + x /          
$$\frac{24 \left(\frac{16 x^{4}}{\left(x^{2} + 2\right)^{2}} - \frac{12 x^{2}}{x^{2} + 2} + 1\right)}{\left(x^{2} + 2\right)^{3}}$$