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Derivative of (-9/4)*sin(2*t)

Function f() - derivative -N order at the point
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The solution

You have entered [src]
-9*sin(2*t)
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     4     
9sin(2t)4- \frac{9 \sin{\left(2 t \right)}}{4}
-9*sin(2*t)/4
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Let u=2tu = 2 t.

    2. The derivative of sine is cosine:

      ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

    3. Then, apply the chain rule. Multiply by ddt2t\frac{d}{d t} 2 t:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: tt goes to 11

        So, the result is: 22

      The result of the chain rule is:

      2cos(2t)2 \cos{\left(2 t \right)}

    So, the result is: 9cos(2t)2- \frac{9 \cos{\left(2 t \right)}}{2}


The answer is:

9cos(2t)2- \frac{9 \cos{\left(2 t \right)}}{2}

The graph
02468-8-6-4-2-1010-1010
The first derivative [src]
-9*cos(2*t)
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     2     
9cos(2t)2- \frac{9 \cos{\left(2 t \right)}}{2}
The second derivative [src]
9*sin(2*t)
9sin(2t)9 \sin{\left(2 t \right)}
The third derivative [src]
18*cos(2*t)
18cos(2t)18 \cos{\left(2 t \right)}