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Derivative of -4x+4/(x+1)^3

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The solution

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          4    
-4*x + --------
              3
       (x + 1) 
4x+4(x+1)3- 4 x + \frac{4}{\left(x + 1\right)^{3}}
-4*x + 4/(x + 1)^3
Detail solution
  1. Differentiate 4x+4(x+1)3- 4 x + \frac{4}{\left(x + 1\right)^{3}} term by term:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: xx goes to 11

      So, the result is: 4-4

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let u=(x+1)3u = \left(x + 1\right)^{3}.

      2. Apply the power rule: 1u\frac{1}{u} goes to 1u2- \frac{1}{u^{2}}

      3. Then, apply the chain rule. Multiply by ddx(x+1)3\frac{d}{d x} \left(x + 1\right)^{3}:

        1. Let u=x+1u = x + 1.

        2. Apply the power rule: u3u^{3} goes to 3u23 u^{2}

        3. Then, apply the chain rule. Multiply by ddx(x+1)\frac{d}{d x} \left(x + 1\right):

          1. Differentiate x+1x + 1 term by term:

            1. Apply the power rule: xx goes to 11

            2. The derivative of the constant 11 is zero.

            The result is: 11

          The result of the chain rule is:

          3(x+1)23 \left(x + 1\right)^{2}

        The result of the chain rule is:

        3(x+1)4- \frac{3}{\left(x + 1\right)^{4}}

      So, the result is: 12(x+1)4- \frac{12}{\left(x + 1\right)^{4}}

    The result is: 412(x+1)4-4 - \frac{12}{\left(x + 1\right)^{4}}

  2. Now simplify:

    412(x+1)4-4 - \frac{12}{\left(x + 1\right)^{4}}


The answer is:

412(x+1)4-4 - \frac{12}{\left(x + 1\right)^{4}}

The graph
02468-8-6-4-2-1010-200000200000
The first derivative [src]
        12   
-4 - --------
            4
     (x + 1) 
412(x+1)4-4 - \frac{12}{\left(x + 1\right)^{4}}
The second derivative [src]
   48   
--------
       5
(1 + x) 
48(x+1)5\frac{48}{\left(x + 1\right)^{5}}
The third derivative [src]
 -240   
--------
       6
(1 + x) 
240(x+1)6- \frac{240}{\left(x + 1\right)^{6}}