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Identical expressions
log((x+ two)/(-x+ two))
logarithm of ((x plus 2) divide by ( minus x plus 2))
logarithm of ((x plus two) divide by ( minus x plus two))
logx+2/-x+2
log((x+2) divide by (-x+2))
Similar expressions
log((x+2)/(x+2))
log((x-2)/(-x+2))
log((x+2)/(-x-2))

The derivative of the function/ log((x+2)/(-x+2))

Derivative of log((x+2)/(-x+2))

The solution

You have entered [src]

   /x + 2 \
log|------|
   \-x + 2/

$$\log{\left(\frac{x + 2}{2 - x} \right)}$$

log((x + 2)/(-x + 2))

Detail solution

Let $u = \frac{x + 2}{2 - x}$ .
The derivative of $\log{\left(u \right)}$ is $\frac{1}{u}$ .
Then, apply the chain rule. Multiply by $\frac{d}{d x} \frac{x + 2}{2 - x}$ :
1. Apply the quotient rule, which is:
  
  $\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}$
  
  $f{\left(x \right)} = x + 2$ and $g{\left(x \right)} = 2 - x$ .
  
  To find $\frac{d}{d x} f{\left(x \right)}$ :
  1. Differentiate $x + 2$ term by term:
    1. The derivative of the constant $2$ is zero.
    2. Apply the power rule: $x$ goes to $1$
    The result is: $1$
  To find $\frac{d}{d x} g{\left(x \right)}$ :
  1. Differentiate $2 - x$ term by term:
    1. The derivative of the constant $2$ is zero.
    2. The derivative of a constant times a function is the constant times the derivative of the function.
      1. Apply the power rule: $x$ goes to $1$
      So, the result is: $-1$
    The result is: $-1$
  Now plug in to the quotient rule:
  
  $\frac{4}{\left(2 - x\right)^{2}}$
The result of the chain rule is:

$\frac{4 \left(2 - x\right)}{\left(2 - x\right)^{2} \left(x + 2\right)}$
Now simplify:

$- \frac{4}{x^{2} - 4}$

The answer is:

$- \frac{4}{x^{2} - 4}$

The graph

Plot the graph f(x)

Plot the graph f'(x)

The first derivative [src]

/  1        x + 2  \         
|------ + ---------|*(-x + 2)
|-x + 2           2|         
\         (-x + 2) /         
-----------------------------
            x + 2

$$\frac{\left(2 - x\right) \left(\frac{1}{2 - x} + \frac{x + 2}{\left(2 - x\right)^{2}}\right)}{x + 2}$$

Simplify

The second derivative [src]

/    2 + x \ /    1        1  \
|1 - ------|*|- ------ - -----|
\    -2 + x/ \  -2 + x   2 + x/
-------------------------------
             2 + x

$$\frac{\left(1 - \frac{x + 2}{x - 2}\right) \left(- \frac{1}{x + 2} - \frac{1}{x - 2}\right)}{x + 2}$$

Simplify

The third derivative [src]

  /    2 + x \ /    1          1              1        \
2*|1 - ------|*|--------- + -------- + ----------------|
  \    -2 + x/ |        2          2   (-2 + x)*(2 + x)|
               \(-2 + x)    (2 + x)                    /
--------------------------------------------------------
                         2 + x

$$\frac{2 \left(1 - \frac{x + 2}{x - 2}\right) \left(\frac{1}{\left(x + 2\right)^{2}} + \frac{1}{\left(x - 2\right) \left(x + 2\right)} + \frac{1}{\left(x - 2\right)^{2}}\right)}{x + 2}$$

Simplify

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Derivative of log((x+2)/(-x+2))

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The solution