/x + 2 \ log|------| \-x + 2/
log((x + 2)/(-x + 2))
Let .
The derivative of is .
Then, apply the chain rule. Multiply by :
Apply the quotient rule, which is:
and .
To find :
Differentiate term by term:
The derivative of the constant is zero.
Apply the power rule: goes to
The result is:
To find :
Differentiate term by term:
The derivative of the constant is zero.
The derivative of a constant times a function is the constant times the derivative of the function.
Apply the power rule: goes to
So, the result is:
The result is:
Now plug in to the quotient rule:
The result of the chain rule is:
Now simplify:
The answer is:
/ 1 x + 2 \ |------ + ---------|*(-x + 2) |-x + 2 2| \ (-x + 2) / ----------------------------- x + 2
/ 2 + x \ / 1 1 \ |1 - ------|*|- ------ - -----| \ -2 + x/ \ -2 + x 2 + x/ ------------------------------- 2 + x
/ 2 + x \ / 1 1 1 \ 2*|1 - ------|*|--------- + -------- + ----------------| \ -2 + x/ | 2 2 (-2 + x)*(2 + x)| \(-2 + x) (2 + x) / -------------------------------------------------------- 2 + x