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ln(2x^2-3)

Derivative of ln(2x^2-3)

Function f() - derivative -N order at the point
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Piecewise:

The solution

You have entered [src]
   /   2    \
log\2*x  - 3/
log(2x23)\log{\left(2 x^{2} - 3 \right)}
d /   /   2    \\
--\log\2*x  - 3//
dx               
ddxlog(2x23)\frac{d}{d x} \log{\left(2 x^{2} - 3 \right)}
Detail solution
  1. Let u=2x23u = 2 x^{2} - 3.

  2. The derivative of log(u)\log{\left(u \right)} is 1u\frac{1}{u}.

  3. Then, apply the chain rule. Multiply by ddx(2x23)\frac{d}{d x} \left(2 x^{2} - 3\right):

    1. Differentiate 2x232 x^{2} - 3 term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: x2x^{2} goes to 2x2 x

        So, the result is: 4x4 x

      2. The derivative of the constant (1)3\left(-1\right) 3 is zero.

      The result is: 4x4 x

    The result of the chain rule is:

    4x2x23\frac{4 x}{2 x^{2} - 3}

  4. Now simplify:

    4x2x23\frac{4 x}{2 x^{2} - 3}


The answer is:

4x2x23\frac{4 x}{2 x^{2} - 3}

The graph
02468-8-6-4-2-1010-2525
The first derivative [src]
  4*x   
--------
   2    
2*x  - 3
4x2x23\frac{4 x}{2 x^{2} - 3}
The second derivative [src]
  /          2  \
  |       4*x   |
4*|1 - ---------|
  |            2|
  \    -3 + 2*x /
-----------------
            2    
    -3 + 2*x     
4(4x22x23+1)2x23\frac{4 \left(- \frac{4 x^{2}}{2 x^{2} - 3} + 1\right)}{2 x^{2} - 3}
The third derivative [src]
     /           2  \
     |        8*x   |
16*x*|-3 + ---------|
     |             2|
     \     -3 + 2*x /
---------------------
                2    
     /        2\     
     \-3 + 2*x /     
16x(8x22x233)(2x23)2\frac{16 x \left(\frac{8 x^{2}}{2 x^{2} - 3} - 3\right)}{\left(2 x^{2} - 3\right)^{2}}
The graph
Derivative of ln(2x^2-3)