Derivative of е^x(2x+5)

1. Apply the product rule:

   $$\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}$$

   $f{\left(x \right)} = e^{x}$; to find $\frac{d}{d x} f{\left(x \right)}$:

   1. The derivative of $e^{x}$ is itself.

   $g{\left(x \right)} = 2 x + 5$; to find $\frac{d}{d x} g{\left(x \right)}$:

   1. Differentiate $2 x + 5$ term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

         1. Apply the power rule: $x$ goes to $1$

         So, the result is: $2$

      2. The derivative of the constant $5$ is zero.

      The result is: $2$

   The result is: $\left(2 x + 5\right) e^{x} + 2 e^{x}$

2. Now simplify:

   $$\left(2 x + 7\right) e^{x}$$

The answer is:

$$\left(2 x + 7\right) e^{x}$$