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Derivative of cos(x^2+4*x+1)/(x+2)

Function f() - derivative -N order at the point
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Piecewise:

The solution

You have entered [src]
   / 2          \
cos\x  + 4*x + 1/
-----------------
      x + 2      
$$\frac{\cos{\left(\left(x^{2} + 4 x\right) + 1 \right)}}{x + 2}$$
cos(x^2 + 4*x + 1)/(x + 2)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Let .

    2. The derivative of cosine is negative sine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. Differentiate term by term:

          1. Apply the power rule: goes to

          2. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: goes to

            So, the result is:

          The result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
     / 2          \                / 2          \
  cos\x  + 4*x + 1/   (4 + 2*x)*sin\x  + 4*x + 1/
- ----------------- - ---------------------------
              2                  x + 2           
       (x + 2)                                   
$$- \frac{\left(2 x + 4\right) \sin{\left(\left(x^{2} + 4 x\right) + 1 \right)}}{x + 2} - \frac{\cos{\left(\left(x^{2} + 4 x\right) + 1 \right)}}{\left(x + 2\right)^{2}}$$
The second derivative [src]
  /   /     2      \                                                   \
  |cos\1 + x  + 4*x/            2    /     2      \      /     2      \|
2*|----------------- - 2*(2 + x) *cos\1 + x  + 4*x/ + sin\1 + x  + 4*x/|
  |            2                                                       |
  \     (2 + x)                                                        /
------------------------------------------------------------------------
                                 2 + x                                  
$$\frac{2 \left(- 2 \left(x + 2\right)^{2} \cos{\left(x^{2} + 4 x + 1 \right)} + \sin{\left(x^{2} + 4 x + 1 \right)} + \frac{\cos{\left(x^{2} + 4 x + 1 \right)}}{\left(x + 2\right)^{2}}\right)}{x + 2}$$
The third derivative [src]
  /                             /     2      \        /     2      \     /         2    /     2      \      /     2      \\                               \
  |       /     2      \   6*sin\1 + x  + 4*x/   3*cos\1 + x  + 4*x/   3*\2*(2 + x) *cos\1 + x  + 4*x/ + sin\1 + x  + 4*x//            2    /     2      \|
2*|- 6*cos\1 + x  + 4*x/ - ------------------- - ------------------- + ---------------------------------------------------- + 4*(2 + x) *sin\1 + x  + 4*x/|
  |                                     2                     4                                     2                                                     |
  \                              (2 + x)               (2 + x)                               (2 + x)                                                      /
$$2 \left(4 \left(x + 2\right)^{2} \sin{\left(x^{2} + 4 x + 1 \right)} - 6 \cos{\left(x^{2} + 4 x + 1 \right)} + \frac{3 \left(2 \left(x + 2\right)^{2} \cos{\left(x^{2} + 4 x + 1 \right)} + \sin{\left(x^{2} + 4 x + 1 \right)}\right)}{\left(x + 2\right)^{2}} - \frac{6 \sin{\left(x^{2} + 4 x + 1 \right)}}{\left(x + 2\right)^{2}} - \frac{3 \cos{\left(x^{2} + 4 x + 1 \right)}}{\left(x + 2\right)^{4}}\right)$$