2 cos (x)
cos(x)^2
Let u=cos(x)u = \cos{\left(x \right)}u=cos(x).
Apply the power rule: u2u^{2}u2 goes to 2u2 u2u
Then, apply the chain rule. Multiply by ddxcos(x)\frac{d}{d x} \cos{\left(x \right)}dxdcos(x):
The derivative of cosine is negative sine:
The result of the chain rule is:
Now simplify:
The answer is:
-2*cos(x)*sin(x)
/ 2 2 \ 2*\sin (x) - cos (x)/
8*cos(x)*sin(x)