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Derivative of 5cos(4x^2)

Function f() - derivative -N order at the point
v

The graph:

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The solution

You have entered [src]
     /   2\
5*cos\4*x /
$$5 \cos{\left(4 x^{2} \right)}$$
5*cos(4*x^2)
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Let .

    2. The derivative of cosine is negative sine:

    3. Then, apply the chain rule. Multiply by :

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result of the chain rule is:

    So, the result is:


The answer is:

The graph
The first derivative [src]
         /   2\
-40*x*sin\4*x /
$$- 40 x \sin{\left(4 x^{2} \right)}$$
The second derivative [src]
    /   2    /   2\      /   2\\
-40*\8*x *cos\4*x / + sin\4*x //
$$- 40 \left(8 x^{2} \cos{\left(4 x^{2} \right)} + \sin{\left(4 x^{2} \right)}\right)$$
The third derivative [src]
      /       /   2\      2    /   2\\
320*x*\- 3*cos\4*x / + 8*x *sin\4*x //
$$320 x \left(8 x^{2} \sin{\left(4 x^{2} \right)} - 3 \cos{\left(4 x^{2} \right)}\right)$$