Derivative of 3log2x-e^2

1. Differentiate $3 \log{\left(2 x \right)} - e^{2}$ term by term:

   1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let $u = 2 x$.

      2. The derivative of $\log{\left(u \right)}$ is $\frac{1}{u}$.

      3. Then, apply the chain rule. Multiply by $\frac{d}{d x} 2 x$:

         1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: $x$ goes to $1$

            So, the result is: $2$

         The result of the chain rule is:

         $$\frac{1}{x}$$

      So, the result is: $\frac{3}{x}$

   2. The derivative of the constant $- e^{2}$ is zero.

   The result is: $\frac{3}{x}$

The answer is: