Derivative of 2e^x-3•4^x+5

1. Differentiate $- 3 \cdot 4^{x} + 2 e^{x} + 5$ term by term:

   1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. The derivative of $e^{x}$ is itself.

      So, the result is: $2 e^{x}$

   2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. The derivative of a constant times a function is the constant times the derivative of the function.

         1. $\frac{d}{d x} 4^{x} = 4^{x} \log{\left(4 \right)}$

         So, the result is: $3 \cdot 4^{x} \log{\left(4 \right)}$

      So, the result is: $- 3 \cdot 4^{x} \log{\left(4 \right)}$

   3. The derivative of the constant $5$ is zero.

   The result is: $- 3 \cdot 4^{x} \log{\left(4 \right)} + 2 e^{x}$

2. Now simplify:

   $$- 6 \cdot 4^{x} \log{\left(2 \right)} + 2 e^{x}$$

The answer is: