Mister Exam

Derivative of 2sin(x+1)-0.5

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
2*sin(x + 1) - 1/2
$$2 \sin{\left(x + 1 \right)} - \frac{1}{2}$$
2*sin(x + 1) - 1/2
Detail solution
  1. Differentiate term by term:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. The derivative of sine is cosine:

      3. Then, apply the chain rule. Multiply by :

        1. Differentiate term by term:

          1. Apply the power rule: goes to

          2. The derivative of the constant is zero.

          The result is:

        The result of the chain rule is:

      So, the result is:

    2. The derivative of the constant is zero.

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
2*cos(x + 1)
$$2 \cos{\left(x + 1 \right)}$$
The second derivative [src]
-2*sin(1 + x)
$$- 2 \sin{\left(x + 1 \right)}$$
The third derivative [src]
-2*cos(1 + x)
$$- 2 \cos{\left(x + 1 \right)}$$