Mister Exam

Lang:

How to use it?
Canonical form:
x=-3-2/3*sqrt(8+2y-y^2)
11x^2-20xy-4y^2-8y+1=0
4x^2-4xy+y^2-14x-8y-2=0
2x^2+2(sqrt8)xy-5y^2
Plot:
x^2/3+y^2/4=1
x^2/2+y^2/8=1
4*(x^2)+9*(y^2)=36
2*x^3-9*x^2-3=y
Identical expressions
x=- three - two / three *sqrt(eight + two y-y^2)
x equally minus 3 minus 2 divide by 3 multiply by square root of (8 plus 2y minus y squared )
x equally minus three minus two divide by three multiply by square root of (eight plus two y minus y squared )
x=-3-2/3*√(8+2y-y^2)
x=-3-2/3*sqrt(8+2y-y2)
x=-3-2/3*sqrt8+2y-y2
x=-3-2/3*sqrt(8+2y-y²)
x=-3-2/3*sqrt(8+2y-y to the power of 2)
x=-3-2/3sqrt(8+2y-y^2)
x=-3-2/3sqrt(8+2y-y2)
x=-3-2/3sqrt8+2y-y2
x=-3-2/3sqrt8+2y-y^2
x=-3-2 divide by 3*sqrt(8+2y-y^2)
Similar expressions
x=-3-2/3*sqrt(8-2y-y^2)
x=-3-2/3*sqrt(8+2y+y^2)
x=-3+2/3*sqrt(8+2y-y^2)
x=+3-2/3*sqrt(8+2y-y^2)

x=-3-2/3*sqrt(8+2y-y^2) canonical form

The teacher will be very surprised to see your correct solution 😉

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             ______________    
            /      2           
        2*\/  8 - y  + 2*y     
3 + x + ------------------- = 0
                 3

$$x + \frac{2 \sqrt{- y^{2} + 2 y + 8}}{3} + 3 = 0$$

x + 2*sqrt(-y^2 + 2*y + 8)/3 + 3 = 0