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(x-6)*(y-8)=0; (y-5):x+y-11=3

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The solution

You have entered [src]
(x - 6)*(y - 8) = 0
$$\left(x - 6\right) \left(y - 8\right) = 0$$
y - 5             
----- + y - 11 = 3
  x               
$$\left(y + \frac{y - 5}{x}\right) - 11 = 3$$
y + (y - 5)/x - 11 = 3
Rapid solution
$$x_{1} = \frac{1}{2}$$
=
$$\frac{1}{2}$$
=
0.5

$$y_{1} = 8$$
=
$$8$$
=
8
$$x_{2} = 6$$
=
$$6$$
=
6

$$y_{2} = \frac{89}{7}$$
=
$$\frac{89}{7}$$
=
12.7142857142857
Numerical answer [src]
x1 = 6.0
y1 = 12.71428571428571
x2 = 0.5
y2 = 8.0
x2 = 0.5
y2 = 8.0