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log3(x)+log3(y)=3; x-y=-6

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The solution

You have entered [src]
log(x)   log(y)    
------ + ------ = 3
log(3)   log(3)    
$$\frac{\log{\left(x \right)}}{\log{\left(3 \right)}} + \frac{\log{\left(y \right)}}{\log{\left(3 \right)}} = 3$$
x - y = -6
$$x - y = -6$$
x - y = -6
Rapid solution
$$x_{1} = 3$$
=
$$3$$
=
3

$$y_{1} = 9$$
=
$$9$$
=
9
Numerical answer [src]
x1 = 3.0 - 1.049717535843709e-31*i
y1 = 9.0 - 1.049717535843709e-31*i
x2 = 3.0 + 4.376235044655318e-23*i
y2 = 9.0 + 4.376235044655308e-23*i
x3 = 3.0 - 9.240533093436878e-22*i
y3 = 9.0 - 9.240533093436885e-22*i
x4 = 3.0 + 3.573169922826181e-36*i
y4 = 9.0 + 3.573169922826181e-36*i
x5 = 3.0 - 1.879820797562412e-24*i
y5 = 9.0 - 1.879820797562436e-24*i
x6 = 3.0
y6 = 9.0
x7 = 3.0 - 4.696970984265657e-39*i
y7 = 9.0 - 4.696971334590273e-39*i
x8 = 3.0 - 1.069612002125233e-22*i
y8 = 9.0 - 1.06961200212523e-22*i
x9 = 3.0 + 2.056663166428365e-22*i
y9 = 9.0 + 2.056663166428367e-22*i
x10 = 3.0 + 2.048162986946458e-25*i
y10 = 9.0 + 2.048162986946458e-25*i
x10 = 3.0 + 2.048162986946458e-25*i
y10 = 9.0 + 2.048162986946458e-25*i