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log3x=3-2/logy9; 2^x*0.25^y=8

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                 2     
log(3*x) = 3 - ------*9
               log(y)  
$$\log{\left(3 x \right)} = - 9 \frac{2}{\log{\left(y \right)}} + 3$$
 x  -y    
2 *4   = 8
$$\left(\frac{1}{4}\right)^{y} 2^{x} = 8$$
(1/4)^y*2^x = 8