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log₂x+log₂y=5; 3x-y=20

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The solution

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log(2*x) + log(2*y) = 5
$$\log{\left(2 x \right)} + \log{\left(2 y \right)} = 5$$
3*x - y = 20
$$3 x - y = 20$$
3*x - y = 20
Rapid solution
$$x_{1} = \frac{10}{3} + \frac{\sqrt{400 + 3 e^{5}}}{6}$$
=
$$\frac{10}{3} + \frac{\sqrt{400 + 3 e^{5}}}{6}$$
=
8.17883375843487

$$y_{1} = -10 + \frac{\sqrt{400 + 3 e^{5}}}{2}$$
=
$$-10 + \frac{\sqrt{400 + 3 e^{5}}}{2}$$
=
4.53650127530461