The perfect square
Let's highlight the perfect square of the square three-member
$$\left(4 t^{2} - 5 t\right) - 14$$
To do this, let's use the formula
$$a t^{2} + b t + c = a \left(m + t\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 4$$
$$b = -5$$
$$c = -14$$
Then
$$m = - \frac{5}{8}$$
$$n = - \frac{249}{16}$$
So,
$$4 \left(t - \frac{5}{8}\right)^{2} - \frac{249}{16}$$
/ _____\ / _____\
| 5 \/ 249 | | 5 \/ 249 |
|t + - - + -------|*|t + - - - -------|
\ 8 8 / \ 8 8 /
$$\left(t + \left(- \frac{5}{8} + \frac{\sqrt{249}}{8}\right)\right) \left(t + \left(- \frac{\sqrt{249}}{8} - \frac{5}{8}\right)\right)$$
(t - 5/8 + sqrt(249)/8)*(t - 5/8 - sqrt(249)/8)
General simplification
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$$4 t^{2} - 5 t - 14$$
Rational denominator
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$$4 t^{2} - 5 t - 14$$
Combining rational expressions
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$$t \left(4 t - 5\right) - 14$$
Assemble expression
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$$4 t^{2} - 5 t - 14$$