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Expression simplification/ Fraction Decomposition into the simple/ (x^2+4*x+3)/(x+1)

How do you (x^2+4*x+3)/(x+1) in partial fractions?

An expression to simplify:

The solution

You have entered [src] 
 2          
x  + 4*x + 3
------------
   x + 1
$$\frac{\left(x^{2} + 4 x\right) + 3}{x + 1}$$ 
(x^2 + 4*x + 3)/(x + 1)
General simplification [src] 
3 + x
$$x + 3$$ 
3 + x
Fraction decomposition [src] 
3 + x
$$x + 3$$ 
3 + x
Numerical answer [src] 
(3.0 + x^2 + 4.0*x)/(1.0 + x)
(3.0 + x^2 + 4.0*x)/(1.0 + x)
Powers [src] 
     2      
3 + x  + 4*x
------------
   1 + x
$$\frac{x^{2} + 4 x + 3}{x + 1}$$ 
(3 + x^2 + 4*x)/(1 + x)
Rational denominator [src] 
     2      
3 + x  + 4*x
------------
   1 + x
$$\frac{x^{2} + 4 x + 3}{x + 1}$$ 
(3 + x^2 + 4*x)/(1 + x)
Trigonometric part [src] 
     2      
3 + x  + 4*x
------------
   1 + x
$$\frac{x^{2} + 4 x + 3}{x + 1}$$ 
(3 + x^2 + 4*x)/(1 + x)
Assemble expression [src] 
     2      
3 + x  + 4*x
------------
   1 + x
$$\frac{x^{2} + 4 x + 3}{x + 1}$$ 
(3 + x^2 + 4*x)/(1 + x)
Common denominator [src] 
3 + x
$$x + 3$$ 
3 + x
Combinatorics [src] 
3 + x
$$x + 3$$ 
3 + x
Combining rational expressions [src] 
3 + x*(4 + x)
-------------
    1 + x
$$\frac{x \left(x + 4\right) + 3}{x + 1}$$ 
(3 + x*(4 + x))/(1 + x)
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