Mister Exam

Lang:

How to use it?
How do you in partial fractions?:
(12*p+1)/(p^3+3*p^2+2*p+3)
atan(((2*sin(2*x))/(1+cos(2*x))+1)/sqrt(3))/sqrt(3)
(7-5*m)/(m-4)+4*m/(m+4)*(m*m-16)/(4*m)+(9*m-23)/(m-4)
((5*c-c^2)/(25*c^2-10*c+1)+4/(1-25*c^2)):(1-(3/(5c-1)))
Factor polynomial:
x^3-x^2-x+20
x^3-x-2*x^2
x^3-x^2-3*x+27
x^3-x^2-3*x+2
Least common denominator:
m^2-4/m^2+6*m+9*m+3/m-2
exp(x)/(2*sqrt(1-exp(2*x)/4))
exp(x)/2+exp(-x)/2
exp(x)/(1-x)+exp(x)/(1-x)^2
Factor squared:
y^2+13*y*b-4*b^2
y^2-12*y*x+7*x^2
-y^2+10*y*x+x^2
y^2-11*y+1
Identical expressions
(twelve *p+ one)/(p^ three + three *p^ two + two *p+ three)
(12 multiply by p plus 1) divide by (p cubed plus 3 multiply by p squared plus 2 multiply by p plus 3)
(twelve multiply by p plus one) divide by (p to the power of three plus three multiply by p to the power of two plus two multiply by p plus three)
(12*p+1)/(p3+3*p2+2*p+3)
12*p+1/p3+3*p2+2*p+3
(12*p+1)/(p³+3*p²+2*p+3)
(12*p+1)/(p to the power of 3+3*p to the power of 2+2*p+3)
(12p+1)/(p^3+3p^2+2p+3)
(12p+1)/(p3+3p2+2p+3)
12p+1/p3+3p2+2p+3
12p+1/p^3+3p^2+2p+3
(12*p+1) divide by (p^3+3*p^2+2*p+3)
Similar expressions
(12*p+1)/(p^3+3*p^2-2*p+3)
(12*p-1)/(p^3+3*p^2+2*p+3)
(12*p+1)/(p^3-3*p^2+2*p+3)
(12*p+1)/(p^3+3*p^2+2*p-3)

How do you (12p+1)/(p^3+3p^2+2*p+3) in partial fractions?

You have entered [src]

      12*p + 1     
-------------------
 3      2          
p  + 3*p  + 2*p + 3

$$\frac{12 p + 1}{\left(2 p + \left(p^{3} + 3 p^{2}\right)\right) + 3}$$

(12*p + 1)/(p^3 + 3*p^2 + 2*p + 3)

Fraction decomposition [src]

(1 + 12*p)/(3 + p^3 + 2*p + 3*p^2)

$$\frac{12 p + 1}{p^{3} + 3 p^{2} + 2 p + 3}$$

      1 + 12*p     
-------------------
     3            2
3 + p  + 2*p + 3*p

General simplification [src]

      1 + 12*p     
-------------------
     3            2
3 + p  + 2*p + 3*p

$$\frac{12 p + 1}{p^{3} + 3 p^{2} + 2 p + 3}$$

(1 + 12*p)/(3 + p^3 + 2*p + 3*p^2)

Numerical answer [src]

(1.0 + 12.0*p)/(3.0 + p^3 + 2.0*p + 3.0*p^2)

(1.0 + 12.0*p)/(3.0 + p^3 + 2.0*p + 3.0*p^2)

Powers [src]

      1 + 12*p     
-------------------
     3            2
3 + p  + 2*p + 3*p

$$\frac{12 p + 1}{p^{3} + 3 p^{2} + 2 p + 3}$$

(1 + 12*p)/(3 + p^3 + 2*p + 3*p^2)

Assemble expression [src]

      1 + 12*p     
-------------------
     3            2
3 + p  + 2*p + 3*p

$$\frac{12 p + 1}{p^{3} + 3 p^{2} + 2 p + 3}$$

(1 + 12*p)/(3 + p^3 + 2*p + 3*p^2)

Rational denominator [src]

      1 + 12*p     
-------------------
     3            2
3 + p  + 2*p + 3*p

$$\frac{12 p + 1}{p^{3} + 3 p^{2} + 2 p + 3}$$

(1 + 12*p)/(3 + p^3 + 2*p + 3*p^2)

Common denominator [src]

      1 + 12*p     
-------------------
     3            2
3 + p  + 2*p + 3*p

$$\frac{12 p + 1}{p^{3} + 3 p^{2} + 2 p + 3}$$

(1 + 12*p)/(3 + p^3 + 2*p + 3*p^2)

Combining rational expressions [src]

       1 + 12*p      
---------------------
3 + p*(2 + p*(3 + p))

$$\frac{12 p + 1}{p \left(p \left(p + 3\right) + 2\right) + 3}$$

(1 + 12*p)/(3 + p*(2 + p*(3 + p)))

Combinatorics [src]

      1 + 12*p     
-------------------
     3            2
3 + p  + 2*p + 3*p

$$\frac{12 p + 1}{p^{3} + 3 p^{2} + 2 p + 3}$$

(1 + 12*p)/(3 + p^3 + 2*p + 3*p^2)

Trigonometric part [src]

      1 + 12*p     
-------------------
     3            2
3 + p  + 2*p + 3*p

$$\frac{12 p + 1}{p^{3} + 3 p^{2} + 2 p + 3}$$

(1 + 12*p)/(3 + p^3 + 2*p + 3*p^2)

How do you (12*p+1)/(p^3+3*p^2+2*p+3) in partial fractions?