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How do you 1/(x^6+1) in partial fractions?

You have entered [src]

  1   
------
 6    
x  + 1

$$\frac{1}{x^{6} + 1}$$

1/(x^6 + 1)

Fraction decomposition [src]

1/(3*(1 + x^2)) - (-2 + x^2)/(3*(1 + x^4 - x^2))

$$- \frac{x^{2} - 2}{3 \left(x^{4} - x^{2} + 1\right)} + \frac{1}{3 \left(x^{2} + 1\right)}$$

                       2    
    1            -2 + x     
---------- - ---------------
  /     2\     /     4    2\
3*\1 + x /   3*\1 + x  - x /

Numerical answer [src]

1/(1.0 + x^6)

1/(1.0 + x^6)

Combinatorics [src]

          1           
----------------------
/     2\ /     4    2\
\1 + x /*\1 + x  - x /

$$\frac{1}{\left(x^{2} + 1\right) \left(x^{4} - x^{2} + 1\right)}$$

1/((1 + x^2)*(1 + x^4 - x^2))