Mister Exam

Lang:

How to use it?
How do you in partial fractions?:
sqrt(1-x^2)/(1-x^2)
(p^2+7p)/(p^2+14p+49)
c^6*u^6/(c^2)^3
acos((b3^2+b4^2-b2^2)/(2*b3*b4))
Factor polynomial:
y^3-9*y
y^3+64
y^3+49+7+y^2
y^3+4^3
Least common denominator:
(x/sqrt(x^2-y^2))^2+(-y/sqrt(x^2-y^2))^2
(x-sqrt(6)+8)/(4-sqrt(x))*(2+sqrt(x))*(4/(16+x^2)+x*(4+x)^2/(256-x^4))
x^cos(1/x)*(cos(1/x)/x+log(x)*sin(1/x)/x^2)
(((x-8)/(x+8))-((x+8)*(x-8)))/8*x/(x^2-64)
Factor squared:
-y^4+5*y^2-11
y^4+4*y^2-13
y^4-3*y^2-2
y^4+3*y^2+2
Identical expressions
acos((b3^ two +b4^ two -b two ^ two)/(2*b3*b4))
arc co sinus of e of ine of ((b3 squared plus b4 squared minus b2 squared ) divide by (2 multiply by b3 multiply by b4))
arc co sinus of e of ine of ((b3 to the power of two plus b4 to the power of two minus b two to the power of two) divide by (2 multiply by b3 multiply by b4))
acos((b32+b42-b22)/(2*b3*b4))
acosb32+b42-b22/2*b3*b4
acos((b3²+b4²-b2²)/(2*b3*b4))
acos((b3 to the power of 2+b4 to the power of 2-b2 to the power of 2)/(2*b3*b4))
acos((b3^2+b4^2-b2^2)/(2b3b4))
acos((b32+b42-b22)/(2b3b4))
acosb32+b42-b22/2b3b4
acosb3^2+b4^2-b2^2/2b3b4
acos((b3^2+b4^2-b2^2) divide by (2*b3*b4))
Similar expressions
acos((b3^2+b4^2+b2^2)/(2*b3*b4))
acos((b3^2-b4^2-b2^2)/(2*b3*b4))
arccos((b3^2+b4^2-b2^2)/(2*b3*b4))

How do you acos((b3^2+b4^2-b2^2)/(2b3b4)) in partial fractions?

You have entered [src]

    /  2     2     2\
    |b3  + b4  - b2 |
acos|---------------|
    \    2*b3*b4    /

$$\operatorname{acos}{\left(\frac{- b_{2}^{2} + \left(b_{3}^{2} + b_{4}^{2}\right)}{2 b_{3} b_{4}} \right)}$$

acos((b3^2 + b4^2 - b2^2)/(((2*b3)*b4)))

General simplification [src]

    /  2     2     2\
    |b3  + b4  - b2 |
acos|---------------|
    \    2*b3*b4    /

$$\operatorname{acos}{\left(\frac{- b_{2}^{2} + b_{3}^{2} + b_{4}^{2}}{2 b_{3} b_{4}} \right)}$$

acos((b3^2 + b4^2 - b2^2)/(2*b3*b4))

Fraction decomposition [src]

acos(b3/(2*b4) + b4/(2*b3) - b2^2/(2*b3*b4))

$$\operatorname{acos}{\left(- \frac{b_{2}^{2}}{2 b_{3} b_{4}} + \frac{b_{3}}{2 b_{4}} + \frac{b_{4}}{2 b_{3}} \right)}$$

    /                  2  \
    | b3     b4      b2   |
acos|---- + ---- - -------|
    \2*b4   2*b3   2*b3*b4/

Numerical answer [src]

acos((b3^2 + b4^2 - b2^2)/(((2*b3)*b4)))

acos((b3^2 + b4^2 - b2^2)/(((2*b3)*b4)))

Rational denominator [src]

    /  2     2     2\
    |b3  + b4  - b2 |
acos|---------------|
    \    2*b3*b4    /

$$\operatorname{acos}{\left(\frac{- b_{2}^{2} + b_{3}^{2} + b_{4}^{2}}{2 b_{3} b_{4}} \right)}$$

acos((b3^2 + b4^2 - b2^2)/(2*b3*b4))

Trigonometric part [src]

    /  2     2     2\
    |b3  + b4  - b2 |
acos|---------------|
    \    2*b3*b4    /

$$\operatorname{acos}{\left(\frac{- b_{2}^{2} + b_{3}^{2} + b_{4}^{2}}{2 b_{3} b_{4}} \right)}$$

acos((b3^2 + b4^2 - b2^2)/(2*b3*b4))

Common denominator [src]

    /                  2  \
    | b3     b4      b2   |
acos|---- + ---- - -------|
    \2*b4   2*b3   2*b3*b4/

$$\operatorname{acos}{\left(- \frac{b_{2}^{2}}{2 b_{3} b_{4}} + \frac{b_{3}}{2 b_{4}} + \frac{b_{4}}{2 b_{3}} \right)}$$

acos(b3/(2*b4) + b4/(2*b3) - b2^2/(2*b3*b4))

Combining rational expressions [src]

    /  2     2     2\
    |b3  + b4  - b2 |
acos|---------------|
    \    2*b3*b4    /

$$\operatorname{acos}{\left(\frac{- b_{2}^{2} + b_{3}^{2} + b_{4}^{2}}{2 b_{3} b_{4}} \right)}$$

acos((b3^2 + b4^2 - b2^2)/(2*b3*b4))

Powers [src]

    /  2     2     2\
    |b3  + b4  - b2 |
acos|---------------|
    \    2*b3*b4    /

$$\operatorname{acos}{\left(\frac{- b_{2}^{2} + b_{3}^{2} + b_{4}^{2}}{2 b_{3} b_{4}} \right)}$$

    /  2     2     2\
    |b3    b4    b2 |
    |--- + --- - ---|
    | 2     2     2 |
acos|---------------|
    \     b3*b4     /

$$\operatorname{acos}{\left(\frac{- \frac{b_{2}^{2}}{2} + \frac{b_{3}^{2}}{2} + \frac{b_{4}^{2}}{2}}{b_{3} b_{4}} \right)}$$

acos((b3^2/2 + b4^2/2 - b2^2/2)/(b3*b4))

Combinatorics [src]

    /                  2  \
    | b3     b4      b2   |
acos|---- + ---- - -------|
    \2*b4   2*b3   2*b3*b4/

$$\operatorname{acos}{\left(- \frac{b_{2}^{2}}{2 b_{3} b_{4}} + \frac{b_{3}}{2 b_{4}} + \frac{b_{4}}{2 b_{3}} \right)}$$

acos(b3/(2*b4) + b4/(2*b3) - b2^2/(2*b3*b4))

How do you acos((b3^2+b4^2-b2^2)/(2*b3*b4)) in partial fractions?