General simplification
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$$x^{2} + x + \frac{1}{4}$$
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + x\right) + \frac{1}{4}$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = \frac{1}{4}$$
Then
$$m = \frac{1}{2}$$
$$n = 0$$
So,
$$\left(x + \frac{1}{2}\right)^{2}$$
Assemble expression
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$$x^{2} + x + \frac{1}{4}$$
$$\frac{\left(2 x + 1\right)^{2}}{4}$$
Combining rational expressions
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1 + 4*x*(1 + x)
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4
$$\frac{4 x \left(x + 1\right) + 1}{4}$$
$$x^{2} + x + \frac{1}{4}$$
$$x^{2} + x + \frac{1}{4}$$
Rational denominator
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2
1 + 4*x + 4*x
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4
$$\frac{4 x^{2} + 4 x + 1}{4}$$
$$x^{2} + x + \frac{1}{4}$$