Mister Exam
Factor polynomial x^2-6*x-2
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} - 6 x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -6$$
$$c = -2$$
Then
$$m = -3$$
$$n = -11$$
So,
$$\left(x - 3\right)^{2} - 11$$
$$\left(x^{2} - 6 x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -6$$
$$c = -2$$
Then
$$m = -3$$
$$n = -11$$
So,
$$\left(x - 3\right)^{2} - 11$$
Factorization
[src]
/ ____\ / ____\ \x + -3 + \/ 11 /*\x + -3 - \/ 11 /
$$\left(x + \left(-3 + \sqrt{11}\right)\right) \left(x + \left(- \sqrt{11} - 3\right)\right)$$
(x - 3 + sqrt(11))*(x - 3 - sqrt(11))