Let's take the limit x→∞lim(−x4+x3) Let's divide numerator and denominator by x^4: x→∞lim(−x4+x3) = x→∞lim(x41−1+x1) Do Replacement u=x1 then x→∞lim(x41−1+x1)=u→0+lim(u4u−1) = 0−1=−∞
The final answer: x→∞lim(−x4+x3)=−∞
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type