Let's take the limit x→∞limx9 Let's divide numerator and denominator by x^9: x→∞limx9 = x→∞limx911 Do Replacement u=x1 then x→∞limx911=u→0+limu91 = 01=∞
The final answer: x→∞limx9=∞
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type