$$\lim_{x \to \infty}\left(\frac{x^{\frac{8}{15}} \sin{\left(x^{2} \right)}}{x + 1}\right) = 0$$
$$\lim_{x \to 0^-}\left(\frac{x^{\frac{8}{15}} \sin{\left(x^{2} \right)}}{x + 1}\right) = 0$$
More at x→0 from the left$$\lim_{x \to 0^+}\left(\frac{x^{\frac{8}{15}} \sin{\left(x^{2} \right)}}{x + 1}\right) = 0$$
More at x→0 from the right$$\lim_{x \to 1^-}\left(\frac{x^{\frac{8}{15}} \sin{\left(x^{2} \right)}}{x + 1}\right) = \frac{\sin{\left(1 \right)}}{2}$$
More at x→1 from the left$$\lim_{x \to 1^+}\left(\frac{x^{\frac{8}{15}} \sin{\left(x^{2} \right)}}{x + 1}\right) = \frac{\sin{\left(1 \right)}}{2}$$
More at x→1 from the right$$\lim_{x \to -\infty}\left(\frac{x^{\frac{8}{15}} \sin{\left(x^{2} \right)}}{x + 1}\right) = 0$$
More at x→-oo