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x-log(1+x^2)

Limit of the function x-log(1+x^2)

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 lim  \x - log\1 + x //
x->-oo                 
$$\lim_{x \to -\infty}\left(x - \log{\left(x^{2} + 1 \right)}\right)$$
Limit(x - log(1 + x^2), x, -oo)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to -\infty}\left(x - \log{\left(x^{2} + 1 \right)}\right) = -\infty$$
$$\lim_{x \to \infty}\left(x - \log{\left(x^{2} + 1 \right)}\right) = \infty$$
More at x→oo
$$\lim_{x \to 0^-}\left(x - \log{\left(x^{2} + 1 \right)}\right) = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(x - \log{\left(x^{2} + 1 \right)}\right) = 0$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(x - \log{\left(x^{2} + 1 \right)}\right) = 1 - \log{\left(2 \right)}$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(x - \log{\left(x^{2} + 1 \right)}\right) = 1 - \log{\left(2 \right)}$$
More at x→1 from the right
Rapid solution [src]
-oo
$$-\infty$$
The graph
Limit of the function x-log(1+x^2)